Solve it with suitable identity.a² + b²- c² - Brainly.in
Nov 3, 2023 · The expression a2 + b2 −c2 doesn't directly match a well-known mathematical identity. However, it resembles the Pythagorean identity, which is a2 +b2 = c2 in a right triangle. If you're …
Verify the equation a² + b² = c² - Brainly.in
Dec 24, 2024 · A2 + b2 + c2 formula says (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca. It is derived from (a + b + c)2 formula as follows.We just read that by multiplying (a …
What is the formula of a2+b2 - Brainly.in
Sep 5, 2021 · A2 + b2 = (a+b)2 - 2ab nd a2 - b2 = (a + b) (a - b)The a2 + b2 + c2 formula is one of the important algebraic identities. It is read as a square plus b square pl…
Proof that (a-b-c)²=a²+b²+c²-2 (ab-bc+ac) - Brainly.in
Jun 28, 2021 · Answer: What is the formula for (a+b+c)²? The formula is: a2+b2+c2+2ab+2bc+2ca PROOF:- (a+b+c)2 can be written as (a+b+c)∗ (a+b+c) , Therefore, (a+b+c)2= (a+b+c)∗ (a+b+c) =a …
(x + a)(x + b)(x + c) = x3 – 10x2 + 45x – 15, then a2 + b2 + c2 is ...
Sep 26, 2024 · (x + a) (x + b) (x + c) = x3 – 10x2 + 45x – 15, then a2 + b2 + c2 is equal to also pls give step by step and hard to under - 61184072
If a2 +b2 +c2 =250 and ab+bc+ca=3, find a+b+c. - Brainly.in
Jun 3, 2015 · If a2 +b2 +c2 =250 and ab+bc+ca=3, find a+b+c. Is this the question you’re looking for?
Find the value of ab+bc+ca, if a+b+c=9 and a2+b2+c2=35 - Brainly
Jun 7, 2016 · Click here 👆 to get an answer to your question ️ Find the value of ab+bc+ca, if a+b+c=9 and a2+b2+c2=35
Verify the algebraic identity (a+b+c)2 =a2+b2+c2+2ab+2bc+2ca by …
Sep 26, 2020 · Answer: objective To verify the identity (a + b)2 = a2 + 2ab + b2 by paper cutting and pasting. Prerequisite Knowledge Area of a square = (side)2. Area of a rectangle = l x b. Materials …
If a2 + b2 + c2 = 90 & a + b + c = 20. Find the value of ab + bc - Brainly
Jun 28, 2019 · Find an answer to your question If a2 + b2 + c2 = 90 & a + b + c = 20. Find the value of ab + bc + ca?
If a2+b2+c2=90and a+b+c=20,then find the value of ab+bc+ca
Sep 22, 2016 · Answer: Given a 2 b 2 c 2 = 90 and also a b c = 20 Squaring on both sides ( a b c ) 2 = 400 ( a 2 b 2 c 2 ) 2 ( a b b c c a ) = 400 2 ( a b b c c a ) = 400 − 90 = 310 a b b c c a = 155